SOLUTION: 3x^3 y^2-3x^2 y^2+3xy^2=

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Question 200531: 3x^3 y^2-3x^2 y^2+3xy^2=
Answer by jim_thompson5910(35256) About Me  (Show Source):
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3x%5E3y%5E2-3x%5E2y%5E2%2B3xy%5E2 Start with the given expression


3xy%5E2%28x%5E2-x%2B1%29 Factor out the GCF 3xy%5E2

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Answer:

So 3x%5E3y%5E2-3x%5E2y%5E2%2B3xy%5E2 factors to 3xy%5E2%28x%5E2-x%2B1%29

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