SOLUTION: Consider the following function
f(x)=x^2-sqrt x
find the equation of the line tangent to the graph at the point (9,78)
y(x)=
can someone help please
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-> SOLUTION: Consider the following function
f(x)=x^2-sqrt x
find the equation of the line tangent to the graph at the point (9,78)
y(x)=
can someone help please
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Question 200393: Consider the following function
f(x)=x^2-sqrt x
find the equation of the line tangent to the graph at the point (9,78)
y(x)=
can someone help please Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Consider the following function
f(x)=x^2-sqrt x
find the equation of the line tangent to the graph at the point (9,78)
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The slope m is 2x - (1/2)x^(-1/2)
m = 2x - (1/2sqrt(x))
At x = 9, m = 2*9 - (1/6)
m = 107/6
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y-78 = (107/6)*(x-9)
y = 107x/6 - 107*3/2 + 78
y = 107x/6 - 165/2 slope-intercept from
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6y - 468 = 107x - 5778
107x - 6y = 5310 standard form
