Question 200361: you have 100 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area. What is the maximum area? One side of the rectangle is 50-x and the other is x.
Answer by RAY100(1637)   (Show Source):
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L = (50-x),,,,,,,,,,,,,,W=(x),,,,,,,,,,,,,Area= (L*W)
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50,,,,,,,,,,,,,,,,,,,,,,,,,,0,,,,,,,,,,,,,,,,,,,,,,0
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26,,,,,,,,,,,,,,,,,,,,,,,,24,,,,,,,,,,,,,,,,,,624
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25,,,,,,,,,,,,,,,,,,,,,,,,25,,,,,,,,,,,,,,,,,,625,,,,,,,,,,,,max
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24,,,,,,,,,,,,,,,,,,,,,,,,26,,,,,,,,,,,,,,,,,,624
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0,,,,,,,,,,,,,,,,,,,,,,,,,,50,,,,,,,,,,,,,,,,,,,,,0
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