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Question 200078: the equation of y=-7/3x+5/3 perpendicular and passing through the point (1,-7) in slope intercept form
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! the equation of y=-7/3x+5/3 perpendicular and passing through the point (1,-7) in slope intercept form
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y = (-7/3)x + 5/3 is in slope-intercept for, so its slope, m, is -7/3.
Lines perpendicular to it have a slope that's the negative inverse, or +3/7.
Then use
y-y1 = m*(x-x1) where (x1,y1) is the point
y+7 = (3/7)*(x-1)
y+7 = (3/7)x - 3/7
y = (3/7)x - 52/7
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