Question 199873: Hi, I need some help with a homework assignment, I want to add the populations (Ca & Pa) together then P(E)= # of outcomes that are favorable / total # of outcomes.
Researchers find that the 2004 population of California was 35,893,799, the 2004 population of Pennsylvania was 12,406,292, and the total US population was 293,655,404. What is the probability that a randomly selected US resident did not live in California? Round to the nearest thousandth of a percent.
Any help is welcome. Val
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! I'm not sure why you want to add in Pennsylvannia. They just want to know the probability of selecting someone who is NOT from California. Are you missing part of the question? Anyways....
Number of people who do NOT live in California = Number people in US - Number of people who live in California
Number of people who do NOT live in California = 293,655,404 - 35,893,799 = 257,761,605
So
Number of people who do NOT live in California = 257,761,605
"What is the probability that a randomly selected US resident did not live in California? "
So the probability of selecting a US resident that does NOT live in California is...
P(NOT California) = # who do NOT live in California/# total
P(NOT California) = 257,761,605/293,655,404
P(NOT California) = 0.877769
So the percentage is 87.7769% which rounds to 87.777% (to the nearest thousandth of a percent).
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