SOLUTION: what values of x cannot possibly be solutions of the following equation? LOGa(3x+1)=2

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Question 199628: what values of x cannot possibly be solutions of the following equation?
LOGa(3x+1)=2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Recall that you CANNOT evaluate the log of a negative value or 0. So this means that 3x%2B1%3E0


3x%2B1%3E0 Start with the given inequality.


3x%3E0-1 Subtract 1 from both sides.


3x%3E-1 Combine like terms on the right side.


x%3E-1%2F3 Divide both sides by 3 to isolate x.




This means that any values of x that are either equal to -1%2F3 or are less than -1%2F3 are NOT allowed.