SOLUTION: The perimeter of a rectangle 36m. The width is 18 yd less than twice the length. Find the length and width of the rectangle.
Algebra
->
Coordinate Systems and Linear Equations
->
Linear Equations and Systems Word Problems
-> SOLUTION: The perimeter of a rectangle 36m. The width is 18 yd less than twice the length. Find the length and width of the rectangle.
Log On
Linear Solvers
Linear
Practice
Practice
Answers archive
Answers
Word Problems
Word
Lessons
Lessons
In depth
In
Click here to see ALL problems on Linear Equations And Systems Word Problems
Question 199357
:
The perimeter of a rectangle 36m. The width is 18 yd less than twice the length. Find the length and width of the rectangle.
Answer by
checkley77(12844)
(
Show Source
):
You can
put this solution on YOUR website!
W=2L
P=2W+2L
36=2(2L)+2L
36=4L+2L
36=6L
L=36/6
L=6 ANS. FOR THE LENGTH.
W=2*6=12 ANS. FOR THE WIDTH.
pROOF:
36=2*12+2^6
36=24+12
36=36