Question 199131: algebraically find all zeros of the funtion- f(x)=x^3-x^2-2x and show all work you did algebraically to find the zeros
Found 2 solutions by nerdybill, RAY100:
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! f(x)=x^3-x^2-2x
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To find the zeros, set f(x)=0 and solve for x:
0=x^3-x^2-2x
0=x(x^2-x-2)
0=x(x-2)(x+1)
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Setting each term (on the right) to zero we get:
x = {0,2,-1}
Answer by RAY100(1637)  (Show Source):
You can put this solution on YOUR website! f(x) =y = x^3 -x^2 -2x
factor
0 = x( x^2 -x -2 )
0 = x (x+1)(x-2)
x=0,,,,,,x+1 =0,,,,,,,x-2 =0
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x=0,,,-1,,,,,,+2
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check by inserting zeros in original,,,,ok
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