SOLUTION: 7[2x-4-2(x+1)]=7x+3

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Question 199086: 7[2x-4-2(x+1)]=7x+3
Found 2 solutions by jim_thompson5910, RAY100:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
... Start with the given equation.


... Distribute


... Distribute again


-42=7x%2B3 Combine like terms on the left side.


0=7x%2B3%2B42 Add 42 to both sides.


0-7x=3%2B42 Subtract 7x from both sides.


-7x=3%2B42 Combine like terms on the left side.


-7x=45 Combine like terms on the right side.


x=%2845%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=-45%2F7 Reduce.


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Answer:

So the solution is x=-45%2F7 which approximates to x=-6.429.

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Use order of operations, PEMDAS
.
7[ 2x - 4 -2(x+1)] =7x +3
.
7[ 2x -4 -2x -2)] = 7x + 3
.
7[ -6] = 7x + 3
.
-42 -3 =-45 =7x
.
-45 / 7 = x
.
check by subst into original eqn,,,,ok