SOLUTION: 1. Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be
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Question 199078: 1. Joe has a collection of nickels and dimes that is worth $6.05. If the number of dimes was doubled and the number of nickels was decreased by 10, the value of the coins would be $9.85. How many dimes does he have?
I have no idea where to start with this the best I can do is to subtract 6.05 from 9.85 but I don't know how to find the answer to this problem. I do have to show my work but I am confused. Answer by jim_thompson5910(35256) (Show Source):
Since "Joe has a collection of nickels and dimes worth $6.05", this tells that . Multiply EVERY term by 100 (to make every number whole) to get
So the first equation is
Also, "the number of dimes was doubled and the number of nickels was decreased by 10, the value would be $9.85" means that . Distribute to get . Multiply EVERY term by 100 to make every number positive. So we now get . Add 50 to both sides to get
So the second equation is
So we have the system of equations:
Multiply the both sides of the first equation by -1.
Distribute and multiply.
So we have the new system of equations:
Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this: