SOLUTION: Two cyclists, 90 mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2h later, at what average speed is each cyclist trav
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Question 199039This question is from textbook algebra and trigonometry
: Two cyclists, 90 mi apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2h later, at what average speed is each cyclist traveling? This question is from textbook algebra and trigonometry
You can put this solution on YOUR website! D=RT
90=(X+2X)2
90=3X*2
90=6X
X=90/6
X=15 MPH FOR THE SLOWER CYCLIST.
2*15=30 MPH FOR THE FASTER CYCLIST.
PROOF;
90=(15+30)2
90=45*2
90=90
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