You can put this solution on YOUR website! How do you graph (x-4)^2/16-(y+4)^2/16=1
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I use the FREE software I dl'ed from
www.padowan.dk.com/graph/
You can put this solution on YOUR website! How do you graph (x-4)^2/16-(y+4)^2/16=1
It's a hyperbola with center at (4,-4)
When y = -4, (x-4)^2 = 16
So x-4 = 4 or x-4 = -4
x = 8 or x = 0
Gives you two points: (8,-4) and (0,-4)
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When x = 4, -(y+4)^2 = 1
(y+4)^2 = -1
y is imaginary.
So the hyperbola does not cross the line x = 4.
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The hyperbola opens to the right from (8,-4) and
to the left from (0,-4)
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Cheers,
Stan H.
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