SOLUTION: 2^x^2-14X+41=1/128
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Question 198964
:
2^x^2-14X+41=1/128
Answer by
stanbon(75887)
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2^(x^2-14X+41) = 1/128
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2^(x^2-14X+41) = 2^(-7)
x^2 - 14x + 41 = -7
x^2 -14x + 48 = 0
(x-6)(x-8) = 0
x = 6 or x = 8
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Cheers,
Stan H.