Question 19892: I need your help with, Factoring Trinomials By Grouping, If the Trinomials cannot be factored write "PRIME"
18p^4+63p^3+27p^2
Answer by vidyamanohar(13)   (Show Source):
You can put this solution on YOUR website! p^4, p^3, p^2 are variable terms present in the expression. we can see p^2 is present in all the terms.
and 18, 63, 27 are the constants we see in the expression
the common factor for all of them is 9 (Reason!!!...we see them in the 9 table)
so, we can take out 9p^2 from the expression and see
9p^2(2p^2+7p+3)
the remaining quadratic factor can be factorized using the usual method of factorisation for quadratics
this is how it goes
9p^2(2p^2+7p+3)=9p^2(2p^2+p+6p+3)=9p^2[p(2p+1)+3(2p+1)]=9p^2(p+3)(2p+1)
hence the factorisation over.
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