SOLUTION: passes through (1,3) and is parellel to the graph of the relation 4x+y=6

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Question 198818: passes through (1,3) and is parellel to the graph of the relation 4x+y=6
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


Given Line Eqn, 4x%2By=6 ---> y=highlight%28-4%29x%2B6 has a Slope=m= -4.

Paralle Lines have the same Slope, m%5B1%5D=m%5B2%5D

Then, thru point (1,3) via Slope-Interecpt Form,
y=mx%2Bb
3=%28-4%29%281%29%2Bb
3=-4%2Bb ===> b=3%2B4=red%287%29, Y-Intercept

It follows ---> red%28y=-4x%2B7%29, or red%284x%2By=7%29, Std Form

Let Fy=0:
4x%2B0=7 ----> cross%284%29x%2Fcross%284%29=7%2F4 ---> x=7%2F4, X-Intercept
(7/4,0) or (1.75,0)

Let Fx=0:
4%280%29y=7
y=7, Y-Intercept


---> red%284x%2By=7%29; green%284x%2By=6%29

Thank you,
Jojo