Question 198682: Lisa was hauling a wide load out of Boston. At 8:00 a.m. she headed west from exit 43 at and average speed of 35 mph. Victor headed west from the same exit at 11 a.m. in his infinity. By 2 p.m. the same day Victor was 15 miles ahead of Lisa. What was Victor's average speed?
At noon the horse and buggy headed noth at 10 mph. Two hours later, the roadster headed south from the same location at 30 mph. At what time will the horse and buggy be 100 miles from the roadster?
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website!
a) Let us compute the Distance travelled by Lisa from 8:00am to 2:00pm (6 hours).
Distance = Speed x time
By 2:00pm, Victor was 15 miles ahead. So, Victor is 225 miles,  by this time.
And Victor's Ave. Speed =  = 
*Note: Victor started driving at 11:00am, and until 2:00pm he covered a distance of 225 miles in  .
Continuing,
 , Answer
b) Given:
Let us calculate the Distance travelled by the horse + buggy in 2 hours before the roadster joined the travel in opposite direction.
 , *remember this
Then,
 ----> 
 , Answer
Let us Check,
Thank you,
Jojo
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