SOLUTION: 4x^2+32x-80=0 my answer is (2x-1)(x+10)^2
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Question 198640
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4x^2+32x-80=0 my answer is (2x-1)(x+10)^2
Answer by
stanbon(75887)
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4x^2+32x-80=0
4 is a common factor:
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4(x^2 + 8x - 20) = 0
4(x + 10)(x-2) = 0
x = -10 or x = 2
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Cheers,
Stan H.