|  | 
| 
 
 
| Question 198572:  Could someone help me with these, I had it last year but forgot how it works:
 1) Find a quadratic equation with roots (4+i)and(4-i).
 2) Given the equation x^3-2x^2+x-3=0, what are the possible rational roots??
 3) Find the irratinal roots of the equation; x^3-4x^2+2x+1=0 I should use the quadratic formula to solve the equation, it might sound stupid but I never really understood how to use the quadratic formula =(
 
 Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website!  or  Start with the given solutions. 
 
 
  or  Subtract 4 from both sides (for each equation). 
 
 
  or  Square both sides 
 
 
  or  Square i to get -1 and square -i to get -1 
 
 
  or  Add 1 to both sides. 
 
 Since the equations are the same, we can focus on one equation:
 
 
 
   
 
 
  FOIL 
 
 
  Combine like terms. 
 
 So the quadratic with the roots 4+i and 4-i is
   
 
 
 
 
 
 
 # 2
 
 Any rational zero can be found through this equation
 
 
  where p and q are the factors of the last and first coefficients 
 
 So let's list the factors of -3 (the last coefficient):
 
 
   
 Now let's list the factors of 1 (the first coefficient):
 
 
   
 Now let's divide each factor of the last coefficient by each factor of the first coefficient
 
 
 
   
 
 
 
 
 
 Now simplify
 
 These are all the distinct rational zeros of the function that could occur
 
 
   
 
 
 
 # 3
 
 
 First, let's find the possible rational zeros
 
 
 Any rational zero can be found through this equation
 
 
  where p and q are the factors of the last and first coefficients 
 
 So let's list the factors of 1 (the last coefficient):
 
 
   
 Now let's list the factors of 1 (the first coefficient):
 
 
   
 Now let's divide each factor of the last coefficient by each factor of the first coefficient
 
 
 
   
 
 
 
 
 
 Now simplify
 
 These are all the distinct rational zeros of the function that could occur
 
 
   
 
 Let's see if the possible zero
  is really a root for the function   
 
 So let's make the synthetic division table for the function
  given the possible zero  : 
 Since the remainder
  (the right most entry in the last row) is equal to zero, this means that  is a zero of   
 Take note that the first three values in the bottom row are 1, -3, and -1. So this means that
 
 
 
   
 
 Now all we need to do is solve
  to find the next two zeros: 
 
 Notice we have a quadratic in the form of
  where  ,  , and   
 
 Let's use the quadratic formula to solve for "x":
 
 
 
  Start with the quadratic formula 
 
 
  Plug in  ,  , and   
 
 
  Negate  to get  . 
 
 
  Square  to get  . 
 
 
  Multiply  to get   
 
 
  Rewrite  as   
 
 
  Add  to  to get   
 
 
  Multiply  and  to get  . 
 
 
  or  Break up the expression. 
 
 So the next two zeros are
  or   
 
 ===================================================================================
 
 Answer:
 
 So the three roots are
  ,  or   
 
 where the irrational roots are
  and   
 
 
 
 | 
  
 | 
 |  |  |