SOLUTION: Tiger Woods hits a golf ball into the air. The equation that describs the path of the ball is h=55t-5t^2. There are three questions. (A How high is it the ball after 2 seconds?) (B
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Question 198427: Tiger Woods hits a golf ball into the air. The equation that describs the path of the ball is h=55t-5t^2. There are three questions. (A How high is it the ball after 2 seconds?) (B When will it first reach 140 meters?) (C When will it hit the ground?) Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Tiger Woods hits a golf ball into the air. The equation that describs the path of the ball is h=55t-5t^2. There are three questions.
(A How high is it the ball after 2 seconds?)
h=55t-5t^2
Simply substitute 't' with 2 and solve:
h=55(2)-5(2)^2
h=110-5(4)
h=110-20
h=90 meters
.
(B When will it first reach 140 meters?)
h=55t-5t^2
Subsitute 'h' with 140 meters and solve:
140=55t-5t^2
0=55t-5t^2-140
0=-5t^2+55t-140
0=-t^2+11t-28
0=t^2-11t+28
0=(t-4)(t-7)
t = {4,7}
Ball reaches height at 4 and 7 seconds
.
(C When will it hit the ground?)
h=55t-5t^2
Subsitute 'h' with 0 meters and solve:
0=55t-5t^2
0=11t-t^2
0=-t^2+11t
0=t^2-11t
0=t(t-11)
t = {0,11}
Ball is at 0 meters at 0 seconds and 11 seconds
