Question 198352: Suppose you are shopping at the fruit market. You want to spend no more than $12.00 on apples and bananas. Bananas cost $2 per bunch, and apples cost $4 per bag. Find 3 possible combinations of bananas and apples that you can buy. Write each combination as an ordered pair. Let x be the number of banana bunches, and let y be the number of apple bags.
Please help me solve this problem.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Let x=# of banana bunches and y=# of apple bags
Since "Bananas cost $2 per bunch, and apples cost $4 per bag" and "You want to spend no more than $12.00 on apples and bananas", this means that we have the inequality
Factor out the GCF 2 on the left side
Divide both sides by 2.
Subtract 2y from both sides.
Since "x" is the number of banana bunches, this means that "x" is a whole number that is NOT negative. So . This means that also.
Start with the given inequality.
Add 2y to both sides.
Rearrange the inequality
Divide both sides by 2.
So you can buy at most 3 apple bags. Note: if you bought only apples, then you could only buy bags.
Since you can buy at most 3 apple bags, this means that the possible y values are: 0, 1, 2, and 3
Plug these values back into the equation to get:
---> ---> . So one ordered pair is (6,0). In other words, in this case, you buy 6 banana bunches and no apple bags.
---> ---> . So one ordered pair is (4,1). In other words, in this case, you buy 4 banana bunches and 1 apple bag.
---> ---> . So one ordered pair is (2,2). In other words, in this case, you buy 2 banana bunches and 2 apple bags.
---> ---> . So one ordered pair is (3,0). In other words, in this case, you buy no banana bunches and 3 apple bags.
and so on...
Here are ALL the possible ordered pairs: (0,0), (0,1), (0,2), (0,3), (1,0), (1,1), (1,2), (2,0), (2,1), (2,2), (3,0), (3,1), (4,0), (4,1), (5,0), (6,0)
Take note that you are allowed to spend under $12. So the first ordered pair (0,0) means you did not buy anything.
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