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Question 198310: Harold Hacker recently read in a national golf magazine that the average weekend golfer carries a handicap of 15 strokes and the standard deviation is 4 strokes. Harold manages a local men’s church league and just tallied the end-of-season totals. The 64 players in Harold’s league finished the year with an average handicap of 14 strokes.
a. Set up the null and alternative hypotheses to test if the average handicap in Harold’s league is not the same as the national average reported in the magazine.
b. Test your hypothesis using = 0.02.
c. Find the p value.
d. Based on Harold’s end-of-season data, what can you conclude?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Harold Hacker recently read in a national golf magazine that the average weekend golfer carries a handicap of 15 strokes and the standard deviation is 4 strokes. Harold manages a local men’s church league and just tallied the end-of-season totals. The 64 players in Harold’s league finished the year with an average handicap of 14 strokes.
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a. Set up the null and alternative hypotheses to test if the average handicap in Harold’s league is not the same as the national average reported in the magazine.
Ho: u = 15
Ha: u is not equal to 15
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b. Test your hypothesis using alpha = 0.02:
Test statistic:
t(14) = (14-15)/[4/sqrt(64)] = -2
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c. Find the p value.
p-value for 2-tail test = 2*P(t < -2 with df = 63)
= 2 * 0.0249 = 0.0498
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d. Based on Harold’s end-of-season data, what can you conclude?
Since the p-value is greater than 2%, fail to reject Ho.
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His group's average does not statistically differ from the
declared national average.
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Cheers,
Stan H.
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