SOLUTION: A chemist has two alloys, one of which is 10% gold and 15% lead, and the other of which is 30% gold and 40% lead. How many grams of each of the two alloys should be used to make an

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Question 198300This question is from textbook Intermediate Algebra An Applied Approach
: A chemist has two alloys, one of which is 10% gold and 15% lead, and the other of which is 30% gold and 40% lead. How many grams of each of the two alloys should be used to make an alloy that contains 60g of gold and 88g of lead? This question is from textbook Intermediate Algebra An Applied Approach

Answer by arallie(162) About Me  (Show Source):
You can put this solution on YOUR website!
Make an algebra problem
.10a%2B.30b=60
.15a%2B.40b=88
Solve for a variable and substitute
.10a%2B.30b=60--->a=600-3b
.15%28600-3b%29%2B.40b=88
90-.45b%2B.40b=88
2=.05b
b=40
Substitute
.15a%2B.40%2840%29=88
.15a%2B16=88
.15a=72
a=480
Check
.10%28480%29%2B.30%2840%29=60
48%2B12=60
60
grams of each of the two alloys should be used to make an alloy that contains 60g of gold and 88g of lead
480g of 10/15
40g of 30/40