Question 198255: respected sir,
1] AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
plz help me..
regards,
binita
Answer by vleith(2983)   (Show Source):
You can put this solution on YOUR website! Since A+C results in a two digit result, and addition can't result in more than a carry of 10. Thus, A must be 1.
This also applies to B+D. That is, you can only carry a maximum of 1 out of that addition.
In order to have the high order addition result in "11", C must be 9. That way, the sum of 1+9 plus the carry from the low order addition will yield 1+9+1 = 11.
So now we know that B+D must equal 11 too. There are several values that can be used to get that result. Since C is already used, B and D can;t be 9. But any of several pairs of values for B + D can result in a sum of 11 works.
For instance B,D could be 8,3 or 7,4 or 6,5
|
|
|
