SOLUTION: How do you solve log(2x+3)-logx=1
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Question 198151
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How do you solve log(2x+3)-logx=1
Answer by
stanbon(75887)
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How do you solve log(2x+3)-logx=1
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log[(2x+3)/x] = 1
(2x+3)/x = 10^1
2x+3 = 10x
8x = 3
x = 3/8
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Cheers,
Stan H.