SOLUTION: There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as th

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Question 197923: There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second? I need help setting up the equation...plez. thank you
Found 2 solutions by nerdybill, josmiceli:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second?
.
Let x = number of barrels transferred
then
220 + x = (2/3)(510-x)
.
Now, solve for x:
220 + x = (2/3)(510-x)
Multiply both sides by 3:
660 + 3x = (2)(510-x)
660 + 3x = 1020 - 2x
660 + 5x = 1020
5x = 360
x = 72 barrels

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = barrels of cement to be transferred from 2nd to 1st shed
After transferring:
In shed 1 is 220+%2B+x
In shed 2 is 510+-+x
given:
220+%2B+x+=+%282%2F3%29%2A%28510+-+x%29
Multiply both sides by 3
660+%2B+3x+=+2%2A%28510+-+x%29
660+%2B+3x+=+1020+-+2x
5x+=+1020+-+660
5x+=+360
x+=+72
72 barrels of cement must be transferred from 2nd to 1st shed
check:
220+%2B+x+=+%282%2F3%29%2A%28510+-+x%29
220+%2B+72+=+%282%2F3%29%2A%28510+-+72%29
292+=+%282%2F3%29%2A438
Multiply both sides by 3
876+=+2%2A438
876+=+876
OK