SOLUTION: 109. Diving time. The time t (in seconds) that it takes for a cliff diver to reach the water is determined by the height h (in feet) from which he dives:
t=~((h)/(16))
a) Use t
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t=~((h)/(16))
a) Use t
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Question 197812: 109. Diving time. The time t (in seconds) that it takes for a cliff diver to reach the water is determined by the height h (in feet) from which he dives:
t=~((h)/(16))
a) Use the properties of radicals to simplify this formula.
b) Find the exact time (according to the formula) that it takes a diver to hit the water when diving from a height of 40 feet.
c) Use the graph to estimate the height if a diver takes 2.5 seconds to reach the water.
I need the following problem solved/using ex:109
110. Sky diving. The formula in Exercise 109 accounts for the effect of gravity only on a falling object. According to that formula, how long would it take a sky diver to reach the earth when jumping from 17,000 feet? (A skydiver can actually get about twice as much falling time by spreading out and using the air to slow the fall.)
You can put this solution on YOUR website! Diving time. The time t (in seconds) that it takes for a cliff diver to reach the water is determined by the height h (in feet) from which he dives:
t=~((h)/(16))
write it:
t =
:
a) Use the properties of radicals to simplify this formula.
extract the square root of 1/16 which is 1/4
t =
:
b) Find the exact time (according to the formula) that it takes a diver to hit the water when diving from a height of 40 feet.
t =
Factor inside the radical to reveal a perfect square
t =
Extract the square root of 4 which is 2
t =
which is
t = seconds
:
c) Use the graph to estimate the height if a diver takes 2.5 seconds to reach the water.
Graph: h = 16t^2
Looks like right around 100 ft
:
:
I need the following problem solved/using ex:109
110. Sky diving. The formula in Exercise 109 accounts for the effect of gravity only on a falling object. According to that formula, how long would it take a sky diver to reach the earth when jumping from 17,000 feet? (A skydiver can actually get about twice as much falling time by spreading out and using the air to slow the fall.)
:
t =
Replace h with 17000
t =
t = 32.596 sec