SOLUTION: Please help me find the root for sqrt y^36 Olease help me simplify the expression sqrt 16n Help me to use thee product rule to simplify sqrt 12x^8 Please help me to evalua

Algebra ->  Square-cubic-other-roots -> SOLUTION: Please help me find the root for sqrt y^36 Olease help me simplify the expression sqrt 16n Help me to use thee product rule to simplify sqrt 12x^8 Please help me to evalua      Log On


   

Question 197749: Please help me find the root for sqrt y^36
Olease help me simplify the expression sqrt 16n
Help me to use thee product rule to simplify sqrt 12x^8
Please help me to evaluate the expression for 25^-3/2

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me find the root for sqrt y^36
sqrt%28y%5E36%29
= sqrt%28y%5E18+%2A+y%5E18%29
= y%5E18
.
Please help me simplify the expression sqrt 16n
sqrt%2816n%29
= sqrt%284%2A4%2An%29
= 4sqrt%28n%29
.
Help me to use thee product rule to simplify sqrt 12x^8
sqrt%2812x%5E8%29
= sqrt%282%2A2%2A3%2Ax%5E4%2Ax%5E4%29
= 2x%5E4sqrt%283%29
.
Please help me to evaluate the expression for 25^-3/2
25%5E%28-3%2F2%29
= 1%2F25%5E%283%2F2%29
= 1%2Fsqrt%2825%5E3%29
= 1%2Fsqrt%2825%2A25%2A25%29
= 1%2F%2825%2Asqrt%2825%29%29
= 1%2F%2825%2Asqrt%285%2A5%29%29
= 1%2F%2825%2A5%29
= 1%2F125