Question 197740: write an equation for the line that contains the point (4,-1) and is perpendicular to the equation y= -2/3x + 7
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Remember y=mx+b,,,,and perpendicular lines have slopes that are negative reciprocals
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y= ( -2/3 ) x +7
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slope is -2/3,,,,,slope in perpendicular line is ( +3/2)
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y= 3/2 x +b
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at ( 4,-1)
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(-1) = 3/2 (4) +b
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-1 -6 = b
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-7 = b
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Inserting in y=mx+b,,,,,y= 3/2 x -7
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checking
substitute ( 4, -1) into y = 3/2 x -7
-1 = (3/2)(4) -7 = -1 ,,,,ok
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