Question 197733: write an equation for the line that contains the point (4,-1) and is perpendicular to the equation y=2/3x + 7 Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! first we must find the slope of the equation y=(-2/3)x+7......since this is in point slope form....we can see the slope is -2/3. now we know that any line perpendicular to this line will have a slope that is the negative reciprical of it.....the negative reciprical of -2/3 is 3/2
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now we have the slope 3/2 and a point (4,-1)...using the point slope formula we have
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y-(-1)=(3/2)(x-4)
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y+1=(3/2)x-6 -->y=(3/2)x-7
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