|
Question 197676: I was given the following table
Input (x)--output(y)
1--8
2--14
3--18
4--24
I noticed that there was a pattern in the output with the numbers ending in either an 8 or a 4. I need a rule that explains the pattern. So far I have only come up with that when the input (x) is even, the rule is 5(x)+ 4. When the input (x) is odd, the rule is 5(x) + 3. I am not sure if this is correct or if there can be two different rules for one pattern. Is there a rule that fits every situation on this input/output chart?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I was given the following table
Input (x)--output(y)
1--8
2--14
3--18
4--24
-----------------
Using the point (1,8) and (4,24)
slope = (24-8)/(4-1) = 16/3
---
intercept = ?
8 = (16/3)*1 + b
b = (24/3)-(16/3)
b = 8/3
---
Equation:
y = (16/3)x + (8/3)
---------------------------
Another answer could be
y = (2/3)x^3 -5x^2 + (49/3)X -4
=====================================
Cheers,
Stan H.
|
|
|
| |
