SOLUTION: using FOIL method How would I solve the following equation (2x + 1) (x + 4)

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Question 197440: using FOIL method
How would I solve the following equation
(2x + 1) (x + 4)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%282x%2B1%29%28x%2B4%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%282x%29%2B1%29%28highlight%28x%29%2B4%29 Multiply the First terms:%282%2Ax%29%2A%28x%29=2%2Ax%5E2.


%28highlight%282x%29%2B1%29%28x%2Bhighlight%284%29%29 Multiply the Outer terms:%282%2Ax%29%2A%284%29=8%2Ax.


%282x%2Bhighlight%281%29%29%28highlight%28x%29%2B4%29 Multiply the Inner terms:%281%29%2A%28x%29=x.


%282x%2Bhighlight%281%29%29%28x%2Bhighlight%284%29%29 Multiply the Last terms:%281%29%2A%284%29=4.


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So we have the terms: 2%2Ax%5E2, 8%2Ax, x, 4


2%2Ax%5E2%2B8%2Ax%2Bx%2B4 Now add every term listed above to make a single expression.


2%2Ax%5E2%2B9%2Ax%2B4 Now combine like terms.


So %282x%2B1%29%28x%2B4%29 FOILs to 2%2Ax%5E2%2B9%2Ax%2B4.


In other words, %282x%2B1%29%28x%2B4%29=2%2Ax%5E2%2B9%2Ax%2B4.