SOLUTION: In 1994, the life expectancy of males in a certain country was 69.6 years. In 1998, it was 73.0 years. Let E represent the life expectancy in year t and let t represent the number

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: In 1994, the life expectancy of males in a certain country was 69.6 years. In 1998, it was 73.0 years. Let E represent the life expectancy in year t and let t represent the number      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 197358: In 1994, the life expectancy of males in a certain country was 69.6 years. In 1998, it was 73.0 years. Let E represent the life expectancy in year t and let t represent the number of years since 1994.
E(t)=_t+_
Use the function to predict the life expectancy of males in 2008
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
In 1994, the life expectancy of males in a certain country was 69.6 years.
In 1998, it was 73.0 years. Let E represent the life expectancy in year t
and let t represent the number of years since 1994.
:
Find the slope
In 1994; x1=0 and y1=69.6
In 1998; x2=4 and y2=73
:
Find the slope (m) using the slope equation: m = %28y2-y1%29%2F%28x2-x1%29
m = %2873-69.6%29%2F%284+-+0%29%29 = %283.4%29%2F%284%29 = .85
:
Use the point/slope formula to write the equation; y - y1 = m(x - x1)
y - 69.6 = .85(x - 0)
y = .85x + 69.6
:
therefore:
The Linear function E(t) that fits the data is.
E(t)= .85t + 69.6
:
Use the Function to predict the life expectancy of males in 2008.
This means t=14; substitute 14 for t in the equation
E(14)= .85(14) + 69.6
E(14)= 11.9 + 69.6
E(14)= 81.5 yrs is the life expectancy in 2008