SOLUTION: Hi, I'm having some trouble with parallel and perpendicular lines, can you help me? Find an equation of the line that satisfies the given conditions. through (8, 1); parallel t

Click here to see ALL problems on Equations

Question 197343: Hi, I'm having some trouble with parallel and perpendicular lines, can you help me?
Find an equation of the line that satisfies the given conditions.
through (8, 1); parallel to the line passing through (9, -1) and (-4, -5)
thanks!
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

Step 1: Use the two given points that define the given line and the two-point form of the equation of a line to derive the equation of the given line:

Step 2: Put your equation into slope-intercept form, that is, solve for y so that it looks like:

Then use the slope, m, of the given line that you can determine by inspection of the slope-intercept form of your equation and the fact that:

to determine the slope of the desired line.

Then use this new slope value, the given point, and the point-slope form of the equation of a line to derive the desired equation:

John

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Find an equation of the line that satisfies the given conditions.
through (8, 1); parallel to the line passing through (9, -1) and (-4, -5)
--------------------------
1st: Find the slope
m = (-5--1)/(-4-9) = -4/-13 = 4/13
---------------------
Form: y = mx + b
You know y = 1 when x = 8, and m = 4/13; solve for "b":
1 = (4/13)8 + b
1 = 32/13 + b
b = (13/13)-(32/13)
b = -19/13
-------------------------------
Equation:
y = (4/13)x - (19/13)
==============================
Cheers,
Stan H.