SOLUTION: Hi I'm having some trouble with the following problem: Find an equation of the line that satisfies the given conditions. through (10, 2); perpendicular to the line x - 4y + 4 =

Algebra ->  Equations -> SOLUTION: Hi I'm having some trouble with the following problem: Find an equation of the line that satisfies the given conditions. through (10, 2); perpendicular to the line x - 4y + 4 =      Log On


   

Question 197338: Hi I'm having some trouble with the following problem:
Find an equation of the line that satisfies the given conditions.
through (10, 2); perpendicular to the line x - 4y + 4 = 0
thanks!
Found 2 solutions by solver91311, scott8148:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Already answered this one. See question 197345

http://www.algebra.com/algebra/homework/equations/Equations.faq.question.197345.html

John

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
solving the given equation for y gives ___ y = (1/4)x + 1
so the slope of the given line is 1/4

the slopes of two perpendicular lines are negative reciprocals of each other
so the slope of the new line is -4

using point-slope ___ y - 2 = -4(x - 10) __ or __ y = -4x + 42