Question 197281: One horse costs $1000, one pig costs $200, and one chicken costs only $10. A farmer buys 28 animals for $8500. He bought twice as many pigs as horses. How many of each animal did he buy?
Found 2 solutions by user_dude2008, solver91311:
Answer by user_dude2008(1862)   (Show Source):
Answer by solver91311(24713)  (Show Source):
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The farmer bought h horses, 2h pigs, and c chickens, and the total number of animals is 28, so:
The value of h horses is 1000h, the value of 2h pigs is 400h, and the value of c chickens is 10c, and the total value of the animals is 8500, so:
Multiply the first equation by -10:
Add this new equation to the value equation:
So he bought 6 horses for $6000, twice that many or 12 pigs for $2400, and 28 - (6 + 12) = 10 chickens for $100. 6000 + 2400 + 100 = 8500 -- Answer checks.
John
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