Question 197126: Find the margin of error for each sample. Round each margin of error to the nearest whole percent. Then find an interval that is likely to contain the true population proportion.
1. 18% of 350 students
2. 41% of 2,000 viewers
3. 6% of 525 artists
4. 97% of 4,000 readers
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the margin of error for each sample. Round each margin of error to the nearest whole percent. Then find an interval that is likely to contain the true population proportion.
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Assuming you want 95% confidence, the z-score will be 1.96
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ME = z
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1. 18% of 350 students
ME = 1.96[sqrt(0.18*0.82/350] = 0.04025
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2. 41% of 2,000 viewers
ME = 1.96[sqrt(0.41*0.59/2000) = 0.2156
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I'll leave the last two to you.
3. 6% of 525 artists
4. 97% of 4,000 readers
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Cheers,
Stan H.
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