SOLUTION: Find the approximate value of the tangent to the following functions at the given x-value. Use the algebraic method. a.y = 1/x at x = 1 b.y = 3cos3x at x = 3 c.y = x^3 + 2 at

Algebra ->  Trigonometry-basics -> SOLUTION: Find the approximate value of the tangent to the following functions at the given x-value. Use the algebraic method. a.y = 1/x at x = 1 b.y = 3cos3x at x = 3 c.y = x^3 + 2 at      Log On


   



Question 197103: Find the approximate value of the tangent to the following functions at the given x-value. Use the algebraic method.
a.y = 1/x at x = 1
b.y = 3cos3x at x = 3
c.y = x^3 + 2 at x = 4
d.y = 3^x at x = 4

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the approximate value of the tangent to the following functions at the given x-value. Use the algebraic method.
a.y = 1/x at x = 1
b.y = 3cos3x at x = 3
c.y = x^3 + 2 at x = 4
d.y = 3^x at x = 4
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What is "the value of the tangent"???
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Maybe you mean the slope? I can do that.
a.y = 1/x at x = 1
y' = -1/x^2
at x=1: m = -1
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b.y = 3cos3x at x = 3
y' = -9sin(3x)
at x=3: m = -9*sin(9) (radians)
m = ~ -3.709
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c.y = x^3 + 2 at x = 4
y' = 3x^2
at x = 4 m = 48
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d.y = 3^x at x = 4
y' = 3x^2
at x = 4 m = 48