SOLUTION: solve the inequality: {{{1/3v + 1/4v < 1/2}}} {{{Take the LCM = 3v*4=12v}}} {{{(4+3)/12v<1/2}}} ==> {{{7/12v<1/2}}} multiply both sides with 12v ==> {{{(7(12v))/12v<(1/2)*12v

Algebra ->  Rational-functions -> SOLUTION: solve the inequality: {{{1/3v + 1/4v < 1/2}}} {{{Take the LCM = 3v*4=12v}}} {{{(4+3)/12v<1/2}}} ==> {{{7/12v<1/2}}} multiply both sides with 12v ==> {{{(7(12v))/12v<(1/2)*12v      Log On


   

Question 197098: solve the inequality:
1%2F3v+%2B+1%2F4v+%3C+1%2F2
Take+the+LCM+=+3v%2A4=12v
%284%2B3%29%2F12v%3C1%2F2
==> 7%2F12v%3C1%2F2
multiply both sides with 12v
==> %287%2812v%29%29%2F12v%3C%281%2F2%29%2A12v+
==> 7%3C12v%2F2
==> 6v%3E7
So v%3E7%2F6
number_line%28+600%2C+-10%2C+10%2C+A=7%2F6%29
So the solution is (7%2F6,%2Binfinity)
that is all real values from the 7/6 in the number line,
without including 7/6.
Answer by mathsteacher(28) About Me  (Show Source):