SOLUTION: The width of a poster is 8cm less than the length. the perimeter is more than 184cm. if the measurements are both integers, find the minium dimensions of the poster.
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-> SOLUTION: The width of a poster is 8cm less than the length. the perimeter is more than 184cm. if the measurements are both integers, find the minium dimensions of the poster.
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Question 196998: The width of a poster is 8cm less than the length. the perimeter is more than 184cm. if the measurements are both integers, find the minium dimensions of the poster.
You can put this solution on YOUR website! The width of a poster is 8cm less than the length. the perimeter is more than
184cm. if the measurements are both integers,
find the minimum dimensions of the poster.
:
Let x = the width
then
(x+8) = the length
:
The perimeter equation
2(x+8) + 2x > 184
Divide both sides by 2
x + 8 + x > 92
2x > 92 - 8
2x > 84
x > 84/2
x > 42
:
Make x = 43, then length = 51
:
Minimum perimeter 188 which is: 51 by 43