Question 196883: 1.Find the two numbers whose sum is 108 and whose difference is 24.
2. The cost of 5 tables is the same as the cost of 8 chairs. If the cost of 4 tables and 9 chairs is Rs. 3080, Find the cost of each.
3. Five years ago, A's age was four times B's age, 6 years hence A'age to B'S is 5:2. Find the ages of A and B at present.
4. If the length of a rectangular room is decreased by 2m and its breadth increased by 5m, its area would increase by 80 sq.m. If the length is increased by 3 m and its breadth decreased by 2m, its areea would decrease by 20 sq.m. Find the length and breadth of the room.
Answer by anantha(86)   (Show Source):
You can put this solution on YOUR website! sol:
let the numbers be x,y
sumof these numbers=x+y
difference of these numbers=x-y
according to the problem
sum of these numbers=108
x+y=108
difference of these numbers=24
x-y=24
x-y=24
x=24+y
substitute this equation in x+y=108
24+y+y=108
24+2y=108
subtract 24 on both sides
24+2y-24=108-24
2y=84
dividing by 2 on both sides
2y/2=84/2
y=42
substitute this value in x-y=24
x-42=24
adding 42 on both sides
x-42+42=24+42
x=66
the numbers are 42 and 66
verification:
x+y=66+42=108
x-y=66-42=24
|
|
|
