SOLUTION: Car dealer (A) will rent a compact car for $40 per day and an additional charge of $0.20 per mile. Car dealer (B) will charge only $0.16 per mile but charges $51 per day. If Adam w

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Car dealer (A) will rent a compact car for $40 per day and an additional charge of $0.20 per mile. Car dealer (B) will charge only $0.16 per mile but charges $51 per day. If Adam w      Log On

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Question 196871: Car dealer (A) will rent a compact car for $40 per day and an additional charge of $0.20 per mile. Car dealer (B) will charge only $0.16 per mile but charges $51 per day. If Adam wanted to rent a car for four days, how many miles would Adam have to drive to make car rental agency B a better bargain?
Found 2 solutions by ankor@dixie-net.com, Mathtut:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Car dealer (A) will rent a compact car for $40 per day and an additional charge
of $0.20 per mile. Car dealer (B) will charge only $0.16 per mile but charges
$51 per day. If Adam wanted to rent a car for four days, how many miles would
Adam have to drive to make car rental agency B a better bargain?
:
Let m = no. of miles
:
Dealer A for 4 days equation:
Cost A = .20m + 4(40)
Cost A = .20m + 160
:
Dealer B for 4 days equation
Cost B = .16m + 4(51)
Cost B = .16m + 204
:
Cost A > Cost B
.20m = 160 > .16m + 204
.20m - .16m > 204 - 160
.04m > 44
m > 44%2F.04
m > 1100 miles (I meant "B" would be a better deal when he exceeds 1100 miles)

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
A........ cost=.2x+40(d)......where x is number of miles
:
B....... cost=.16x+51(d).....where d is the number of days
:
.2x+40(4)=.16x+51(4)
:
.2x+160=.16x+204
:
.04x=44
:
x=1100 miles