SOLUTION: log(subscript 3) 8 * log(subscript 8) 9
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Question 196786
:
log(subscript 3) 8 * log(subscript 8) 9
Found 2 solutions by
stanbon, user_dude2008
:
Answer by
stanbon(75887)
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log(subscript 3) 8 * log(subscript 8) 9
---
= [log(8)]/[log(3)]/[log(8)]
Cancel the common factor of log(8) to get:
---
= log(9)/log(3)
= log(base 3)9
= 2
===========
Cheers,
Stan H.
Answer by
user_dude2008(1862)
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Answer: