SOLUTION: __4__ +1= _2c_ 3(c+4) c+4

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Question 196695: __4__ +1= _2c_
3(c+4) c+4
Found 2 solutions by ankor@dixie-net.com, RAY100:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Assume it's:
:
4%2F%283%28c%2B4%29%29 + 1 = %282c%29%2F%28%28c%2B4%29%29
:
Multiply ea term by 3(c+4); results
4 + 3(c+4) = 3(2c)
:
4 + 3c + 12 = 6c
:
4 + 12 = 6c - 3c
:
16 = 3c
c = 16%2F3

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
2 4 c +1 = 1 2 c + 3(c+4) c + 4
.
c=i
.
Reasoning is cumulative, 12c +_2c =_4c resulted in 12c+12c +24c,,,
substituting and collecting terms resulted in 3c^2 =-1, or c=i
.
24(i) +1 = 12(i) +3(i)^2 +12(i) +4
.
checking
.
24i +1 = 12i +3(-1) +12i +4
.
24 i +1 = 24i -3 +4 = 24i +1,,, ok