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| Question 196688:  Find a thrid-degree polynomial with rational coefficients that has roots -5 and 6 + i.
 Answer by RAY100(1637)
      (Show Source): 
You can put this solution on YOUR website! Remember  that  when  an  imaginary  term  is  a  solution,  the  complex  conjugate  is  also .
 x=(-5) ,,,,(x+5)=0
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 x= ( 6+i),,,(x-(6+i) ) =0,,,,(x-6-i) =0
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 and x=(6-i),,,,  (x - (6-i) ) = 0,,,,(x-6+i) =0
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 combining
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 (x+5)(x-6-i) ( x-6+i ) =0
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 (x+5) ( x^2 -6x +ix -6x +36 -6i -xi+6i -i^2 )
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 (x+5) ( x^2 -12x +37)
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 x^3 -12x^2 +37x +5x^2 -60x +185
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 x^3 -7x^2 -23x +185
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 checking
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 with  x=0,,  both  original  and  answer  =185
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 with  x=1,  both  are  156 ,,,,,ok
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 Revised  mon  5-18
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