Question 196616: The perimeter of a rectangular room is 94ft. The length is two feet longer than twice the width. Find the length of this room. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangular room is 94ft. The length is two feet longer than twice the width. Find the length of this room.
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Perimeter = 2(L + W)
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Let L = 2x + 2
Then W = x
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Substitute:
94 = 2(2x+2 + x)
47 = 3x + 2
3x = 45
x = 15 ft. (width of the room)
2x+2 = 32 ft. (length of the room)
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Cheers,
Stan H.