Question 196268: find all rational zeros of p(x)= x^3-12x-16
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! p(x)= x^3-12x-16
I graphed it and found a zero at x = 4
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Then, using synthetic division, I got the following:
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4)....1....0....-12....-16
.......1....4.....4...|..0
Quotient: x^2 + 4x + 4 =0
Factors as (x+2)^2 = 0
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Real Zeroes: x = 4, x = -2 with multiplicity 2
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Cheers,
Stan H.
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