SOLUTION: Hello. I'm having some difficulty figuring out the following word problem, Can you help me? A bottle contains 650 mL of fruit punch with a concentration of 50% pure fruit jui

Algebra ->  Equations -> SOLUTION: Hello. I'm having some difficulty figuring out the following word problem, Can you help me? A bottle contains 650 mL of fruit punch with a concentration of 50% pure fruit jui      Log On


   



Question 196219: Hello.
I'm having some difficulty figuring out the following word problem, Can you help me?
A bottle contains 650 mL of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 mL of the punch and then refills the bottle with an equal amount of a cheaper brand of punch. If the concentration of juice in the bottle is now reduced to 48%, what was the concentration in the punch that Jill added?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If Jill drinks some of the 50% pure fruit juice,
what she drinks has that same concentration
and what is left has that same concentration
What is left is:
650+-+100+=+550 ml of 50% pure fruit juice
She filled up the bottle, replacing what she drank
with cheaper drink with 100 ml of unknown
concentration fruit juice.
Let x = the ml of pure juice in the cheaper drink
In words, I need to write this equation:
(ml of pure juice I end up with)/(total ml of punch) = 48%
%28.5%2A550+%2B+x%29+%2F+650+=+.48
+275+%2B+x+=+.48%2A650
x+=+312+-+275
x+=+37 ml
Now the question is: How much of the cheap drink added was water?
There was 550 ml in the bottle before she added it
She added 37 ml of pure juice, so
550+%2B+37+=+587
The rest of the 650 ml bottle must have been water
650+-+587+=+63ml
And the concentration of the cheap drink was
37%2F%2837+%2B+63%29+=+37%2F100
37% is the answer
check: does the fruit drink + water add up to 650?
fruit drink:
275+%2B+37
water:
275+%2B+63
275+%2B+37+%2B+275+%2B+63+=+650
OK