SOLUTION: The vertex and the axis of symmetry of the graph of y=x^2+5 are

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Question 196127: The vertex and the axis of symmetry of the graph of y=x^2+5 are
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the equation has the form
ax%5E2+%2B+bx+%2B+c, then the
vertex is where x+=+-b%2F%282a%29
In your equation, y+=+x%5E2+%2B+5,
there is no x term and no b,
so b=0 and -b%2F%282a%29+=+0,
x=0 is the axis of symmetry
That is the y-axis.
I already know that x=0 is the
x-coordinate of the vertex. What is
the y-coordinate?
y+=+x%5E2+%2B+5
y+=+0+%2B+5
y+=+5
So, the vertex is at (0,5)
I'll graph it, too
+graph%28+300%2C+300%2C+-5%2C+5%2C+-2%2C+10%2C+x%5E2+%2B+5%29+