Question 196119: The perimeter of a rectangle is 36. The lenght is 3 less than twice the width. Find the width. Answer by anantha(86) (Show Source):
You can put this solution on YOUR website! sol:
let width be x
twice the width is 2x
according to the problem
length= 3 less than twice the width
length=twice the width-3
length=2x-3
width=x
perimeter of the rectangle=2(length+bredth)
perimeter of the rectangle=2(2x-3+x)
perimeter of the rectangle=2(3x-3)
perimeter of the rectangle=6x-6
according to the problem
perimeter of the rectangle =36
6x-6=36
adding 6 on both sides
6x-6+6=36+6
6x=42
dividing by 6 on both sides
6x/6=42/6
x=7
width=7
length=2x-3
length=2*7-3
length=14-3=11
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