SOLUTION: Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 196090: Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x= liters of 10% acid solution needed
In words:
(liters of acid in final solution)/(total liters of solution) = 6%
%28.04%2A10+%2B+.1x%29+%2F+%2810+%2B+x%29+=+.06
Multiply both sides by 10+%2B+x
.4+%2B+.1x+=+.06%2A%2810+%2B+x%29
.4+%2B+.1x+=+.6+%2B+.06x
.04x+=+.6+-+.4
.04x+=+.2
x+=+5
5 liters of 10% acid solution are needed
check answer:
.4+%2B+.1%2A5+=+.06%2A%2810+%2B+5%29
.4+%2B+.5+=+.06%2A15
.9+=+.9
OK